Is the first graph provided in question 5 velocity vs time or v vs position or V vs distance? (The graph indicates that it is V vs X (the description indicates it is v vs time) How could the position keep increasing beyond the amplitude?
in part C of the same problem the solution states that the amplitude from the graph is 0.35 m? how is that obtained from the given graph? If it is V vs time that information is not obtainable from the graph and if it is V vs distance travelled then the amplitude 1/4 wavelength ??????
Jacob, thanks for the input - I removed the first graph as it's not needed and as you pointed out, incorrect. I did add that the student pulled the spring out .35 m, so that would be our delta x for part c. John
John, thank you. but now information about period or velocity is necessary to get to a value for part C or delete the plugged in values in the answer for part C
Jacob, if you look at the graph at time 0, it shows a velocity of 0.16 m/s, which is the maximum velocity, before friction takes hold and slows it down. So assume that's the max velocity. This also means we have to assume that the students didn't start the clock until the pendulum reached its maximum velocity where there was no potential energy, and it was all kinetic. If they started the clock when they released the pendulum, the initial velocity would be zero. Since that assumption is not explicitly stated, I'll add it to the question. But I'd like your opinion on this before I make the change. Thanks! John
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